If A= [2 3] [4 5] matrix find the characteristic roots of A
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Answered by
2
A
1,−4,7
A=
⎣
⎢
⎢
⎡
1
0
0
2
−4
0
3
2
7
⎦
⎥
⎥
⎤
so,By cayley Hamilton theorem,
[∣A−λI∣]=0 is characteristic equation
So,
∣
∣
∣
∣
∣
∣
∣
∣
1−λ
0
0
2
λ−4
0
3
2
7−λ
∣
∣
∣
∣
∣
∣
∣
∣
=0
(1−λ)(λ−4)(7−λ)=0
so,λ=1,4,+7.
these are characteristic solution.
thank you for adding my answer brainlistin list
Answered by
0
Answer:
23 2×4 + 3×5
8+15=23 here 2 and 4 and 3and 5 multiply and the sum is our Answer
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