If A={2,3,5,7,9},B={0,1,2,3,4,5} then verify n(A union B)=n(A)+n(B)-n(A intersection B)?
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Step-by-step explanation:
so easy
n(A union B) =n(A)+n(B)-n(A intersection B)?
n(A union B) = 5+6 - 2
n(A union B)= 5+4
n(A union B) = 9
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