Question

If a=2+√3+√5 and b=3+√3-√5 then find (a-2)^2+(b-3)^2 plzzz answer it. It's urgent.

Answer 1

a=2+root 3+ root5
b=3+root3-root5

=(a-2)^2+(b -3)^2
=(2+root3+root5)^2+(3+root3-root5-3)^2
=(3+5)^2+(3-5)^2
=8^2+(-2)^2
=64+4
=68
solved

thank u