Math, asked by sudhadevisahu, 26 days ago

If a=(2+√3), b=(2-√3), then a²+ab+b² is equal to: ​

Answers

Answered by Mysteryboy01
2

a=(2+√3), b=(2-√3)

 = a²+ab+b²

 = (2 +  \sqrt{3} )^{2}  + (2 +  \sqrt{3} )(2 -  \sqrt{3} ) + (2 -  \sqrt{3} ) ^{2}

 = ( {2)}^{2}  + ( { \sqrt{3} })^{2}  + 2 \times 2 \times  \sqrt{3}  + ( {2}^{2}  +  \sqrt{3}  ^{2} ) +  {2}^{2}  + ( \sqrt{3)}  ^{2}  - 2 \times 2 \times  \sqrt{3}

 = 4 + 3 + 4 \sqrt{3}  + 4 + 3 + 3 - 4 \sqrt{3}

 = 7 + 7 + 3

 = 14 + 3

 = 17

Answered by tagorbisen
1

Answer:

2*2+2*3

4+6

10

Step-by-step explanation:

2*2+2*3

4+6

10

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