if a = 2 + √3 , find a- 1/ a
Anonymous:
hllo
Answers
Answered by
10
Hey friend !!!!!
•°• Here's your answer •°•

Identity used
( a + b ) ( a - b ) = a^2 - b^2
Hope it satisfies you ☆▪☆
Thanks ^_^
☆ Be Brainly ☆
•°• Here's your answer •°•
Identity used
( a + b ) ( a - b ) = a^2 - b^2
Hope it satisfies you ☆▪☆
Thanks ^_^
☆ Be Brainly ☆
Similar questions