If a = 2 + √3, find the value of (a^2 + 1 /^2 )
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1
Answer:
14
Step-by-step explanation:
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Given
———-
a = 2 + Sqrt (3)
Squaring on both sides, we get
a^2 = (2 + Sqrt (3))^2
a^2 = 4 + 3 + 2*2*Sqrt(3)
a^2 = 7 + 4*Sqrt(3) ————> 1
1/a^2 = 1/(7 + 4*Sqrt(3))
Rationalizing
1/a^2 = (7 - 4*Sqrt(3))/((7 + 4*Sqrt(3))*(7 - 4*Sqrt(3))
1/a^2 = (7 - 4*Sqrt(3))/(49 - 48)
1/a^2 = (7 - 4*Sqrt(3)) ———->2
Adding equations 1 & 2,
(a^2 + 1/a^2) = 7 + 4*Sqrt(3) + 7 - 4*Sqrt(3)
(a^2 + 1/a^2) = 14 ——> Answer
———-
a = 2 + Sqrt (3)
Squaring on both sides, we get
a^2 = (2 + Sqrt (3))^2
a^2 = 4 + 3 + 2*2*Sqrt(3)
a^2 = 7 + 4*Sqrt(3) ————> 1
1/a^2 = 1/(7 + 4*Sqrt(3))
Rationalizing
1/a^2 = (7 - 4*Sqrt(3))/((7 + 4*Sqrt(3))*(7 - 4*Sqrt(3))
1/a^2 = (7 - 4*Sqrt(3))/(49 - 48)
1/a^2 = (7 - 4*Sqrt(3)) ———->2
Adding equations 1 & 2,
(a^2 + 1/a^2) = 7 + 4*Sqrt(3) + 7 - 4*Sqrt(3)
(a^2 + 1/a^2) = 14 ——> Answer
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