Question

If a=2+√3
Then
solve = a-1/a​

Answer 1

$a = 2 + \sqrt{3} \\ \frac{1}{a} = \frac{1}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ \frac{1}{a} = \frac{2 - \sqrt{3} }{ {(2)}^{2} - {( \sqrt{3}) }^{2} } \\ \frac{1}{a} = \frac{2 - \sqrt{3} }{4 - 3} \\ \frac{1}{a} = \frac{2 - \sqrt{3} }{1} = 2 - \sqrt{3} \\ - \frac{ 1}{a} = - 2 + \sqrt{3}$
$a - \frac{1}{a} \\ 2 + \sqrt{3} - 2 + \sqrt{3} \\ 2 \sqrt{3}$

Answer 2

hey mate

given here

a= 2+√3

find here

a- 1/a =?

so,

1/a= 1/(2+√3)

=(2-√3)/(2+√3)(2-√3)

= (2-√3) /4-3

=(2-√3)

now,

a - 1/a= (2+√3) -(2-√3)

=2+√3-2+√3

=2√3

i hope its helps u.

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