Question

If a=2^ 3 x 3 , b = 2 * 3 * 5 , c = 3 ^ n * 5 and LCM (a, b, c) = 2 ^ 3 * 3 ^ 2 * 5 , then what is the value of n?​

Answer 1

Answer:

Given:

$a = (2)^{3}(3)\\\\b= (2)(3)(5)\\\\c = 3^{n}(5)$

$LCM(a,b,c) = (2^{3})(3^{2})(5)$

Step-by-step explanation:

Now we can see that we have to see LCM for the 3 powers only as the 2 powers and 5 powers are already mentioned.

Now $LCM(a,b,c) = (2^{3})(3^{2})(5)$ Thus highest power of 3 occuring in given numbers is 2. This n = 2.

Might Help. Thanks!

Answer 2

Step-by-step explanation:

Ans =a=24

B=30

C=3^n*5

Lcm =120*3^n=2^3*3^2*5

120×3^n=360

3^n=3^1

N=1