Math, asked by supraja7, 5 hours ago

if a^2-3a+1=0 then the value of a^2-(1÷a^2)​

Answers

Answered by sumanojha658
0

Answer:

Correct option is

C

11

a2−3a−1=0

=>a2−1=3a

=>a−a1=3

Squaring both sides,

=>(a−a1)2=32

=>a2+a12−2(a)(a1)=9

=>a2+a12=9+2

                           =11

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