If A = (2, 4, 1), B(-1, 0, 1), C=(-1, 4, 2), then the distance of (1, -2, 1) from the plane ABC is
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iske bade
Distance from (1,−2,1) is
2
12
2
4 2
∣4(−1)−3(−2)+12(1)−8∣
=
25+144
−4+6+12−8
=
169
6
=
13/
6
units
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