if A={2,4,6,8,10} and B={3,6,9,12,15}, find A-B and B-A
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Answer:
A−B=2,4,8,10B-A={3,9,12,15}B−A=3,9,12,15
Step-by-step explanation:
Given : if A = { 2,4,6,8,10} and B= {3,6,9,12,15}
To find : The set A-B & B-A ?
Solution :
We know that,
A-B=A-(A\cap B)A−B=A−(A∩B) and B-A=B-(A\cap B)B−A=B−(A∩B)
So, first we find intersection i.e. the common number in both A and B.
A\cap B={2,4,6,8,10}\cap{3,6,9,12,15}A∩B=2,4,6,8,10∩3,6,9,12,15
A\cap B={6}A∩B=6
Now,
A-B=A-(A\cap B)A−B=A−(A∩B)
A-B={2,4,6,8,10}-{6}A−B=2,4,6,8,10−6
A-B={2,4,8,10}A−B=2,4,8,10
and B-A=B-(A\cap B)B−A=B−(A∩B)
B-A={3,6,9,12,15}-{6}B−A=3,6,9,12,15−6
B-A={3,9,12,15}B−A=3,9,12,15
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