Question

if A ={2,4,6,8}
,find P(A) power set of A​

Answer 1

For a given set S with n elements, number of elements in P(S) is 2^n. As each element has two possibilities (present or absent}, possible subsets are 2×2×2.. n times = 2^n. Therefore, power set contains 2^n elements

Answer 2

Answer:

P(A) = { { }-null set,  {2,4,6,8}, {2}, {4}, {6}, {8}, {2,4}, {2,6} {2,8}, {4,6}, {4,8},

            {6,8}, {2,4,6}, {2,4,8}, {4,6,8}, {2,6,8} }

Step-by-step explanation:

The given set is A = {2, 4, 6, 8}

The number of elements in set A = 4

The number of elements in the power set of A is n(P(A)) = $2^{4}$

Therefore the number of elements in the power set of A = 16

The power set of A is given by

P(A) = { { }-null set,  {2,4,6,8}, {2}, {4}, {6}, {8}, {2,4}, {2,6} {2,8}, {4,6}, {4,8},

            {6,8}, {2,4,6}, {2,4,8}, {4,6,8}, {2,6,8} }