Question

If A(-2,4), B(0, 0), C(4, 2) are vertices of AABC. Then the length of median through vertex A is​

Answer 1

Answer:

-2,4 is correct answer

please give me a vote ok

Answer 2

It is given that A(-2,4) B(0,0) and C(4,2). The median is drawn through the vertex A.

The median divides the opposite side it two equal parts.

The midpoint of B and C is

Midpoint=(\frac{0+4}{2},\frac{2+0}{2})=(2,1)Midpoint=(

2

0+4

,

2

2+0

)=(2,1)

The vertex of midpoint (point D) is (2,1)

The distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}d=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

AD=\sqrt{(-2-2)^2+(4-1)^2}=\sqrt{16+9}=5AD=

(−2−2)

2

+(4−1)

2

=

16+9

=5

Therefore the length of the median is 5 units.