If a^2+4b^2=17 and ab=2 find a+2b
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a^2+4b^2=17------(1)
ab=2------(2)
(a+2b)^2 = a^2 +4b^2+2*a*2b
=(17)^2 +4*2 from (1) and (2)
=284+8
=292
therefore
a+2b = root 292
= root (4*73)
= 2 root 73
ab=2------(2)
(a+2b)^2 = a^2 +4b^2+2*a*2b
=(17)^2 +4*2 from (1) and (2)
=284+8
=292
therefore
a+2b = root 292
= root (4*73)
= 2 root 73
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