if a^2-6a-1=0,what will be value of (a-1/a)
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Answer :-
a - 1/a = 6
Explanation :-
Given :-
a² - 6a - 1 = 0
To find :-
a - 1/a
Solution :-
a² - 6a - 1 = 0
Transpose - 1 to RHS [ - 1 becomes 1]
⇒ a² - 6a = 1
Taking 'a' as common value
⇒ a(a - 6) = 1
Transpose a to RHS [Multiplication becomes division]
⇒ a - 6 = 1/a
Transpose 1/a to LHS [ 1/a becomes - 1/a]
⇒ a - 6 - 1/a = 0
Transpose - 6 to RHS [ - 6 becomes 6]
⇒ a - 1/a = 6
Note :-
• These type of questions can be solved by just solving the given equation in terms of constants(numbers i.e, 6).
• The given equation can be solved perfectly when you know transposing rules.
• Transposing rules
1. Addition(+) becomes subtraction(-)
2. Subtraction(-) becomes addition(+)
3. Division becomes multiplication
4. Multiplication becomes division
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