Question

If a^2+6a+x=(a+3)^,2find the value of x

Answer 1

QUESTION :–

● If a²+ 6a + x = (a+3)² then find the value of x

ANSWER :–

x = 9

EXPLANATION :–

GIVEN :–

• An equation a² + 6a + x = (a + 3)²

TO FIND :–

Value of 'x' .

SOLUTION :–

• An equation –

a² + 6a + x = (a + 3)²

• We know that –

=> (a + b)² = a² + b² + 2 ab

• Applying formula in equation –

=> a² + 6a + x = a² + (3)² + 2(a)(3)

=> a² + 6a + x = a² + 9 + 6a

=> a² + 6a + x = a² + 6a + 9

• Now compare –

=> x = 9

EXTRA INFORMATION :–

(1) (a - b)² = a² + b² - 2ab

(2) (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

(3) (a + b - c)² = a² + b² + c² + 2ab - 2bc - 2ca

(4) (a - b + c)² = a² + b² + c² - 2ab - 2bc + 2ca

(5) (- a + b + c)² = a² + b² + c² - 2ab + 2bc - 2ca

Answer 2

AK HAS EXPLAINED VERY WELL ...

TUSEN TAKK