Question

if a=2^8*3,b=2*3*5,c=3^n*5 and lcm(a,b,c)=2^8*3^2*5,then n=?​

Answer 1

Answer:

n =2

Step-by-step explanation:

a=2^8 *3

b= 2*3*5

c = 3^n *5

LCM(a,b,c) = 2^8 *3^2 * 5

LCM (a,b) = 2^8 *3 *5( common multiplier will be counted single time)

now from c we can see that 5 is already in the lcm(a,b,c) but 2 will be needed 2 times

that means 3^n = 3^2

after comparing n =2