Question

If a = 2 and b = 1, then what is the value of log(a+b)(a^2 - b^2) ?

Answer 1

(a+b)(a^2-b^2)=(2+1){(2+1)(2^2-1^2)}
=3{3×(4-1)}
=3{3×3}
=3(9)
=27(or)3^3

Answer 2

Given,

The values of variables $a$ and $b$,

$a=2\\b=1$

To Find,

Value of $log(a+b)(a^{2} - b^{2} )$

Solution,

On substitution of $a$ and $b$ values,

⇒ $log(2+1)(2^{2} -1^{2} )$

⇒$log(3)(4-1)$

⇒$log3^{2}$

⇒$2log3$

On substitution of value of log 3, that is 0.4771,

⇒$2$×$0.4771 = 0.9542$

Henceforth, the value of $log(a+b)(a^{2} - b^{2} )$ is $0.9542$