Math, asked by MathsHwlp, 1 day ago

If a=-2 and b=3 find 2*3+3a*2b+3ab*2+b3

Answers

Answered by mahipanchal6244
1

Answer:

a3 + 3a2 b + 3ab2 + b3 - 8 =

(a3 + 3a2b + 3ab2 + b3) − 8= (a + b)3 - 8 = (a + b)3 − (2)3 =

(a + b -2) {(a + b)2 + (2)2 + 2(a

+ b)} = (a + b - 2) (a2 + b2 + 2ab + 4 + 2a + 2a)

Answered by partha060305
0

Answer:

-1

Step-by-step explanation:

2³ + 3 ( -2)² (3) + 3(-2)(3)² + (3)(3)

= 8 + 36 - 54 + 9

= -54+53

= -1

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