Question

If a = 2 and b = 3, find the value of ab/6 - a^2

Answer 1

Answer:

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Step-by-step explanation:

Equation= $\frac{ab}{6} -a^{2}$

Put a=2 and b=3

⇒$\frac{(2)(3)}{6}-2^{2}$

⇒$\frac{6}{6} -4$

⇒$1-4$

⇒$-3$

Therefore, the value of $\frac{ab}{6} -a^{2}$, when a=2 and b=3 is -3.

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