Question

If a=2 and b=3, find the value of:
(i)a+b
(ii)a²+ab
(iii)ab-a²
(iv)2a-3b
(v)5a²-2ab
(vi)a³-a²​

Answer 1

Given,

a= 2

b= 3

(i) a+b = 2+3 = 5

(ii) a$^2 + ab = 2^2 + 2X3 = 4+6 = 10$

(iii) $ab-a^2 = 2X3-2^2 = 6-4 = 2$

(iv) 2a-3b = 2X2-3X3 = 4-9 = -5

(v) $5a^2 -2ab = 5X(2)^2-2X2X3 = 5X4-12 = 20-12 = 8$

(vi) a³-a² = $2^3-2^2 = 8-4 = 4$

Answer 2

Answer:

(i) 5

(ii) 10

(iii) 2

(iv) -5

(v) 8

(vi) 4

Step-by-step explanation:

(i) a+b=2+3=5

(ii) a^2+ab=2^2+2×3=4+6=10

(iii) ab-a^2=2×3-2^2=6-4=2

(iv) 2a-3b=2×2-3×3=4-9=-5

(v) 5a^2-2ab=5×4-2×6=20-12=8

(vi) a^3-a^2= 2^3-2^2=8-4=4