If (A)=2 and (B)=3
so...
Xy+Yz-Zx = ???
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Answered by
1
Answer:
xy2=a3—−(1)
yz2=b3—(2)
zx2c3—−(3)
(1)∗(2)∗(3)=(xy2)∗(yz2)∗(zx2)=a3b3c3
=>x3y3z3=a3b3c3
=>xyz=abc—−(4)
=>xy=abcz—(5)
(2)∗(3)=(yz2)∗(zx2)=b3c3
=>x2yz3=b3c3
=>x(xy)z3=b3c3
From (5),=>xabczz3=b3c3
=>x=b2c2az2—(6)
Substituting (6) in (3):
z∗(b2c2az2)2=c3
=>b4c4a2z3=c3
=>z3=b4c4a2c3
=>z3=b4ca2
Step-by-step explanation:
hope it's help full
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3
Answer:
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