Question

If a = 2 and b = 3, then the value of (aᵃ + bᵇ) ⁻¹ is equal to ​

Answer 1

Answer:

31

Step-by-step explanation:

putted the value of a and b

(2^2+3^3)^-1

(4+27)^-1

(31)^-1

1/31

(Note:here ^ sign means raise to the power)

hope it will help u

Answer 2

Step-by-step explanation:

ANSWER:-

Given :-

• a = 2
• b = 3

To find:-

(aᵃ + bᵇ) ⁻¹

Concept:-

• To place the values directly in the places of the alphabets.
• Laws of Exponents .

$\sf{(a^a + b^b)^-1}$

$\sf{((2)^2 + (3)^3)^-1}$

$\sf{(4+27)^-1}$

$\sf{(31)^-1}$

$\sf{\dfrac{1}{31}}$

So, $\sf{\dfrac{1}{31}}$ is the answer.

Other than Concept applied:-

• BODMAS was used which tells to simplify Algorithms inside the brackets first.
• Also, we need to note:-

$\sf{(a)^{-n}}$ = $\sf{\dfrac{n}{a}}$

• This is the law of exponent used.