Question

If |A|=2 and |B|=4 and angle between then is 60∘ then |A-B| with explaintion

Answer 1

Solution :

|A−B| $= \sqrt{A^2+B^2-2ABcos0}$

$= \sqrt{A^2+16-2*2*4*\frac{1}{2} }$

$=\sqrt{12} = 2\sqrt{3}$

Hence , our answer is √3.

Answer 2

Answer:

please see on doubtnut