Question

If a=2 and b=a then find the value of(a^b+b^a) ^-1​

Answer 1

Answer:

$\frac{1}{8}$

Step-by-step explanation:

$={({a}^{b}+{b}^{a})}^{-1}$

$={({2}^{2}+{2}^{2})}^{-1}$(a=b=2)

$={(4+4)}^{-1}$

$={8}^{-1}$

$=\frac{1}{8}$

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