If a + ß =π/2
and sin a =1/ 3, then sin B is :
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Step-by-step explanation:
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Step-by-step explanation:
π
A + B=-----
2
1
sinA =------
3
π
sinB= sin(----- - A)
2
= cos A
= √(cosA) ^2
=√ 1- sin^2A
=√ 1-(1/3)^2
= √1-(1/9)
,= √8/9
=2√2/3
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