Question

If a=2 andb =3,find the value of (a^b+b^a)^-¹

Answer 1

Answer:

(2³+3²)-¹

(8+9)-¹

(17)-¹

1/17

Hope it help....

Answer 2

Given, a=2 and b=3

Substituting the values of a & b in

(a^b+b^a)^(-1)

we get,

(2^3+3^2)^(-1)

= (8+9)^(-1)

= (17)^(-1)

= 1/17 {Reason: (m)^-n = 1/(m)^n }