Question

if a=2;b=1;c=0
3a²b+3ab²-3abc​

Answer 1

Step-by-step explanation:

3(2)² * 1 + 3 * 2 (1)² - 3 (2)(1)(0)

3(4) * 1 + 3 * 2 (1) -0

12*1 + 6

12 +6

18

Answer 2

Answer:

18

Step-by-step explanation:

a = 2

b = 1

c = 0

$3a^{2}b+3ab^{2}-3abc = 3\times2^{2}\times1+3\times2\times1^{2}-3\times2\times1\times0$

$3\times2^{2}\times1+3\times2\times1^{2}-3\times2\times1\times0 = 12+6-0 = 18$