Math, asked by saniya6811, 23 days ago

If a=2 , b = -1 , c = 15 find the value of
b {}^{2}  - 4ac

Answers

Answered by saichavan
20

Given :

 \sf \: a = 2, \: b =  - 1, \: c = 15

 \sf \implies \:  {b}^{2}  - 4ac

 \sf \implies \:  {( - 1)}^{2}  - 4 \times 2 \times 15

 \sf \implies \: 1 - 8 \times 15

 \sf \implies \:  {b}^{2} - 4ac =  \green{  - 119}

Additional information-

b²- 4ac > 0 , then roots of quadratic equation are real and unequal.

b²-4ac = 0 , then the roots of quadratic equation are real and equal.

b² - 4ac < 0 , then the roots are not real (i.e. imaginary roots).

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