Question

if a=2, b=1, c=3 then justify (a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

Answer 1

(a+b+c)²
=(2+1+3)²=(6)²=36
a²+b²+c²+2ab+2bc+2ca
=2²+1²+3²+2(2)(1)+2(1)(3)+2(3)(2)
4+1+9+4+6+12
=36
SO
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca

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Answer 2

I hope this is right answer.