Math, asked by plokendro, 18 days ago

If a=2,b=1,then find the value of sum of 2a²+3b²,5a²-2b²+ab and -6a²-5ab+b²

Answers

Answered by kavitapaliwal0921

1

Answer:

a=2 and b=1

then,

2a²+3b²

= 2(2)²+3(1)²

= 2×4+3×1

= 8+3

= 11

5a²-2b²+ab

= 5(2)²-2(1)²+2×1

= 5×4-2+2

= 20-2+2

= 20

-6a²-5ab+b²

= -6(2)²-5×2×1+(1)²

= -24-10+1

= -33

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