Math, asked by jaydeep7148, 7 months ago

If
a=2, b=-11.c=15. Find the value of
C,
(b)2-4ac​

Answers

Answered by nishukaur21
54

Step-by-step explanation:

b²-4ac

-11²-4.2.15

121-120=1

Answered by pulakmath007
5

The value of b² - 4ac = 1

Given :

The expression b² - 4ac

To find :

The value of b² - 4ac for a = 2, b = -11, c = 15

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is b² - 4ac

Step 2 of 2 :

Find the value

The given expression is b² - 4ac

Putting a = 2, b = -11, c = 15 we get

 \sf  {b}^{2}  - 4ac

 \sf   = {( - 11)}^{2}  - 4 \times 2 \times 15

 \sf   = 121 - 120

 \sf   = 1

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