if a^2 +b^2 = 100,ab=48, find the value of a+b
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Answered by
1
Answer:
(a+b)^2=a^2+b^2+2ab
(a+b)^2=100+96
(a+b)^2=196
a+b=14
Answered by
20
a² + b² = 100
ab = 48
(a + b)² = a² + b² + 2ab
(a + b)² = (100) + 2(48)
(a + b)² = 100 + 96
(a + b)² = 196
a + b = √196
a + b = 14
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