Question

if a^2+b^2=11ab and a>b>0,prove that log (a-b/3) =1/2 (loga+logb)

Answer 1

Step-by-step explanation:

please refer to the attachment

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Answer 2

Answer:

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Step-by-step explanation:

Given,

a²+b²=11ab

a²+b²-2ab=9ab

(a-b)²=9ab

a-b=±3√ab

log(⅓(a-b))=½(loga+logb)

log(⅓(3√ab))=½(loga+logb)

log√ab=½(loga+logb)

½logab=½(loga+logb)

½(loga+logb)=½(loga+logb)