Question

If a^2+b^2=13 and ab=6,find 1.)a+b 2.)a-b

Answer 1

Step-by-step explanation:

a^2+b^2=13

(a+b)^2-2ab=13

(a+b)^2-2×6=13

(a+b)^2=13+12

(a+b)^2=25

(a+b)=√25

(a+b)=+,-5Ans

again

(a-b)^2+2ab=13

(a-b)^2=13-2×6

(a-b)^2=1

(a-b)=+,-1

oooo ko finally done thanks

IF i m right then PLZz FALLOW ME

Answer 2

Answer:

a^2 + b^2 =13

ab=6

1.)we know that

(a+b)^2=a^2+b^2+2ab

( a+b)^2= 13+2*6

(a+b)^2 =13+12

(a+b)^2=25

squaring on both sides

(a+b)=5

2.)we know that

(a-b)^2= a^2+b^2-2ab

(a-b)^2=13-2*6

(a-b)^2=13-12

(a-b)^2= 1

squaring on both sides

(a-b)=+or - 1

HOPE IT HELPS YOU