Question

if a^2 + b^2 = 14 ab, show that 2 log (a+b) = 2 log 4 + log a + log b

Answer 1

Answer:

= (a×a) + (b×b)

= 2a + 2b

= 2a + 2b is the answer

Answer 2

$Given a2+b2=14a2b2 or, (+b)2=2</p><p></p><p>Now taking logarithm both sides with respect to the base e we get,</p><p></p><p>2log(a+b)=log16+loga2+logb2</p><p></p><p>or, 2log(a+b)=4log2+2loga+2logb</p><p></p><p>or, log(a+b)=2log2+loga+logb></p><p></p><p>$

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