Question

If a^2 + b^2 = 2 and c^2 + d^2 = 1 then the value of ( ad - bc )^2 + ( ac + bd )^2 is ​

Answer 1

3

add both teams equation and on left hand side add 2abcd and again nullify it with -2abcd, to get desire reault

Answer 2

Step-by-step explanation:

a^2+b^2=2

a^2=2-b^2

a=√2-b^2

a=√2 -b

c^2+d^2=1

c^2=1-d^2

c=1 - d

know

(ad-bc)^2 + (ac + bd)^2

√2d- bd - b+ db ^2 + √2-b × 1-d +bd^2

2d^2 - b^2 + 2 -2d^2

2-b^2..