if a^2+b^2=22ab prove that 2log(a+b)=3log2+log3+loga+logb
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Step-by-step explanation:
Given that a2+b2=7ab
adding 2ab on both sides . we get
a2+b2+2ab=9ab
it can be written as (a+b)2
then (a+b)2= 3^(2) ab
applying log on both sides we get
log(a+b)^2 = log3(^2)ab
so,
2log(a+b)=log a+log b+ 2log3 [since log m^n= n log m]
hence proved
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