if a^2+b^2= 24 and ab=15 (1)a-b (2)a+b
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Answered by
0
Answer:
a+b = 3 root 6
Step-by-step explanation:
a^2 +b^2 =24
add 2ab both sides
a^2+b^2+2ab =24 +2ab
(a+b)^2= 2(ab+12)
ab =15
a+b)^2= 2(15+12)
a+b)^2 = 54
a+b = sqrt 54
a+b = 3 root 6
sim for a-b
subtract -2ab in the a^2+b^2= 24
a^2+b^2- 2ab = 24- 2ab
(a-b)^2=2(12-ab)
a-b)^2=2(12-15)
a-b)^2 = -6
a-b =
i don't know after that
Answered by
1
Step-by-step explanation:
a² + b² = 24 and ab = 15
1.) a - b
(a - b)² = a² + b² - 2ab
=> (a - b)² = 24 - (2 × 15)
=> (a - b)² = 24 - 30
=> a - b = √ (- 6)
=> a - b = + √6
2.) a + b
(a + b)² = a² + b² + 2ab
=> (a + b)² = 24 + 30
=> a + b = √54
=> a + b = + 3√6
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