Math, asked by TheWorker, 10 months ago

if a^2+b^2= 24 and ab=15 (1)a-b (2)a+b​

Answers

Answered by HannanM
0

Answer:

a+b = 3 root 6

Step-by-step explanation:

a^2 +b^2 =24

add 2ab both sides

a^2+b^2+2ab =24 +2ab

(a+b)^2= 2(ab+12)

ab =15

a+b)^2= 2(15+12)

a+b)^2 = 54

a+b = sqrt 54

a+b = 3 root 6

sim for a-b

subtract -2ab in the a^2+b^2= 24

a^2+b^2- 2ab = 24- 2ab

(a-b)^2=2(12-ab)

a-b)^2=2(12-15)

a-b)^2 = -6

a-b =

i don't know after that

Answered by Pragya3918red
1

Step-by-step explanation:

a² + b² = 24 and ab = 15

1.) a - b

(a - b)² = a² + b² - 2ab

=> (a - b)² = 24 - (2 × 15)

=> (a - b)² = 24 - 30

=> a - b = √ (- 6)

=> a - b = + √6

2.) a + b

(a + b)² = a² + b² + 2ab

=> (a + b)² = 24 + 30

=> a + b = √54

=> a + b = + 3√6

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