if a^2+b^2=25 and ab=12 find 3(a+b)^2-5(a-b)^2
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Answer:
142
Step-by-step explanation:
a² + b² = 25
Adding 2ab on both sides
⇒ a² + b² + 2ab = 25 + 2ab
⇒ ( a + b )² = 25 + 2( 12 )
⇒ ( a + b )² = 25 + 24
⇒ ( a + b )² = 49
Using algebraic identity
( a - b )² = ( a + b )² - 4ab
⇒ ( a - b )² = 49 - 4( 12 )
⇒ ( a - b )² = 49 - 48
⇒ ( a - b )² = 1
Now, 3( a + b )² - 5( a - b )²
= 3( 49 ) - 5( 1 )
= 147 - 5
= 142
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