If a^2−b^2=2640 and a^2+b^2=6338 then what is the value of 23ab?
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a^2−b^2=2640--------------->1
a^2+b^2=6338 -------------->2
solving 1 and 2 simultaneous equn,we get,
2a^2 =8978
a^2=4489
a= 67
a^2−b^2=2640
4489-2640 =b^2
b^2=1849
b=43
Step-by-step explanation:
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