Math, asked by dmanojan204, 1 year ago

If a^2−b^2=2640 and a^2+b^2=6338 then what is the value of 23ab?

Answers

Answered by gnsurabhi
0

Answer:

a^2−b^2=2640--------------->1

a^2+b^2=6338 -------------->2

solving 1 and 2 simultaneous equn,we get,

2a^2 =8978

a^2=4489

a= 67

a^2−b^2=2640

4489-2640 =b^2

b^2=1849

b=43

Step-by-step explanation:

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