If a^2+b^2=34 and ab=15 find the value of a+b and a-b
Answers
Answered by
0
Answer:
a+b =+8 or -8
a-2b =+2 or -2
Step-by-step explanation:
a^2+b^2=34
ab=15
(a+b)^2=a^2+b^2+2ab
(a+b)^2=34+2×15
( a+b)^2=64
a+b=√64
a+b=+8 or -8
(a-b)^2=a^2+b^2-2ab
(a - b)^2=34-2×15
(a - b)^2=34-30
(a - b)^2=4
a - b=√4
a - b=+2or-2
Answered by
1
Answer:
a + b = 8
and
a - b = 2
Step-by-step explanation:
given,
a^2 + b^2 = 34 and ab = 15 therefore 2ab = 30
1)we can added 2ab in equation on both sides
we get,
a^2 + b^2 + 2ab = 34 + 2ab
we know that a^2 + b^2 + 2ab = (a +b)^2
therefore (a+b)^2 = 34+30
(a+b)^2 = 64
take the square root on both sides we get
a + b = 8
2) we can subtract 2ab in equation on both side we get
a^2 + b^2 -2ab = 34 - 2ab
(a-b)^2 = 4
therefore a-b = 2
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