Question

if a^2-b^2=36 and a-b =12 then average of a and b is?​

Answer 1

Step-by-step explanation:

the average of a + b will be 3/2

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Answer 2

Given that : a²-b² = 36 .....(1) and

a-b = 12 .....(2)

As we know that : a²-b² = (a-b)(a+b)

=> 36 = 12(a+b)

=> a+b = 3 .....(3)

Now, on adding (2) and (3) :

2a = 15

=> a = 15/2

On putting the value of a in equation (2) :

15/2 - b = 12

=> b = 15/2 - 12

=> b = -9/2

Now, average of a and b = (a+b)/2

$\frac{ \frac{15}{2} + ( \frac{ - 9}{2}) }{2} = \frac{ \frac{15 - 9}{2} }{2} \\ \\ = > \frac{6}{4}$

So, the average of a and b will be 6/4

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