If a^2+b^2=37 and ab= 6,find the value of 1) a+b 2) a-b
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Answered by
1
Step-by-step explanation:
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Answered by
0
Answer:
1) a+b=7 & 2) a-b=5
Step-by-step explanation:
(a+b)^2
=a^2+b^2+2ab
=37+2×6
=37+12
=49
So,(a+b)=√(a+b)^2
=√49
=7【Ans.】
(a-b)^2
=a^2+b^2-2ab
=37-2×12
=25
So,(a-b)
=√(a-b)^2
=√25
=5【Ans.】
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