Math, asked by udaysinghsisodiya998, 1 month ago

If a^2+b^2=37 and ab= 6,find the value of 1) a+b 2) a-b​

Answers

Answered by quantumnpishere
1

Step-by-step explanation:

Hopefully the above attachment will help

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Answered by abirdas378
0

Answer:

1) a+b=7 & 2) a-b=5

Step-by-step explanation:

(a+b)^2

=a^2+b^2+2ab

=37+2×6

=37+12

=49

So,(a+b)=√(a+b)^2

=√49

=7【Ans.】

(a-b)^2

=a^2+b^2-2ab

=37-2×12

=25

So,(a-b)

=√(a-b)^2

=√25

=5【Ans.】

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