Question

if a^2+b^2 =5 and a^2b^2 =3 find the value of a^4+b^4​

Answer 1

Step-by-step explanation:

Given -

a²+b²=5

a²b²=3

now,

(a²+b²)²=5² (squaring both sides)

a^4+b^4+2a²b²=25

a^4+b^4+2×3=25. (a²b²=3 given)

a^4+b^4+6=25

a^4+b^4=25-6

a^4+b^4=19

hope this will help you

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Answer 2

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-if a^2+b^2 =5 and a^2b^2 =3 find the value of a^4+b^4

$\huge\tt\underline\blue{ANSWER }$

------>>>>Here is your answer<<<<--------

$➾ {a}^{2} + {b}^{2} = 5$

$➾ {a}^{2} {b}^{2} = 3$

$➾squaring \: both \: sides$

$➾ {( {a}^{2} + {b}^{2} )}^{2} = {a}^{4} + {b}^{4} + 2 {a}^{2} {b}^{2}$

$➾ {(5)}^{2} = {a}^{4} + {b}^{4} + 2 \times 3$

$➾25 = {a}^{4} + {b}^{4} + 6$

$➾25 - 6 = {a}^{4} + {b}^{4}$

$➾ {a}^{4} + {b}^{4} = 19✓$

HOPE IT HELPS YOU..

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