Math, asked by ballu4, 1 year ago

if a^2 + b^2 = 6 ab then show log a - b / 2 =1/2 ( log a + log b )

Answers

Answered by abhi178
3
a^2 + b^2 =6ab

(a -b)^2 +2ab = 6ab

(a - b)^2 = 4ab

take log both sides

log(a - b)^2 =log4ab

2log(a -b) =log4 +loga +logb

2log(a - b) =2log2 +loga + logb

log(a - b) = log2 +1/2(loga + logb )

log(a -b)-log2 =1/2(loga +logb )

log(a - b)/2 =1/2(loga + logb )





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