Math, asked by ashwin172, 11 months ago

If a^2 + b^2 = 7 and (a - b)^2 = 3, what is the value of ab?​

Answers

Answered by gaurav2244
1

Answer:

1 hope it may help you just have to put the identities and solve it

Attachments:
Answered by N150049
2

Answer:

The value of ab=2.

Step-by-step explanation:

Given values: a²+b²=7,(a-b)²=3

we know that;

(a-b)²= a²+b²-2ab.

Subtitute given values in the above equation.

3=7-2ab

3-7=-2ab⇒-4=-2ab

ab=2.

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