Question

If a^2+b^2=99, ab=9. Find (a-b)^2

Answer 1

Answer:

If a^2+b^2=99, ab=9. Find (a-b)^2

Step-by-step explanation:

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Answer 2

The value of (a-b)² is 81

Given : Value of a^2+b^2=99, ab=9.

To find : The value of (a-b)²

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the value of the given algebraic expression)

Here, we will be using general algebraic formulas.

Given values,

• (a²+b²) = 99
• ab = 9

So,

= (a-b)²

= (a² - 2ab + b²)

= (a²+b² - 2ab)

= [99 - (2×9)]

= 99 - 18

= 81

(This will be considered as the final result.)

Used formula :

• (a-b)² = a²-2ab+b²

Hence, the value of (a-b)² is 81