Question

If a^2+b^2=9andab=4; find the value of 3(a+b)^2-2(a-b)^2​

Answer 1

Answer:

3(a+b)^2-2(a-b)^2​=49

Step-by-step explanation:

Answer 2

Answer:

$= {a}^{2} + {b}^{2} = 9 \\ = ab = 4 \\ now \: 3 {(a + b)}^{2} - 2 {(a - b)}^{2} \\ = 3 ( {a}^{2} + {b}^{2} + 2ab) - 2( {a}^{2} + {b}^{2} - 2ab) \\ = 3(9 + 2 \times 4) - 2(9 - 2 \times 4) \\ = 3(9 + 8) - 2(9 - 8) \\ = 3(17) - 2(1) \\ = 51 - 2 \\ = 49$

I hope this is helpfull for you