Math, asked by dhruvsharma6072, 11 months ago

If a^2 + b^2 + c^2 = 1, then which of the following cannot be a value of (ab + bc + ca)?
A. 0
B. 1/2
C. -1/4
D. -1
full explanation needed. Who explains best gets BRAINLIEST.​

Answers

Answered by Anonymous
11

a² + b² + c² = 1

___________ [ GIVEN ]

• We have to find the value of (ab + bc + ca)

__________________________

We have a² + b² + c² = 1.

ab + bc + ca = ?

We know that..

→ (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Take 2 common

→ a² + b² + c² + 2(ab + bc + ca)

Now put value of a² + b² + c² above

→ (1) + 2(ab + bc + ca)

→ 1 + 2(ab + bc + ca)

→ 2(ab + bc + ca) = - 1

→ ab + bc + ca = -1/2

But the given options are

A. 0

B. 1/2

C. -1/4

D. -1

It means that none of the option is correct.

__________________________

ab + bc + ca = -1/2

_______ [ ANSWER ]

__________________________

Similar questions